1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
|
#!/usr/bin/env python3
#
# Utility functions to parse the XLSX menu for the Daily Bulletin
# Copyright (C) 2024 Runxi Yu <https://runxiyu.org>
#
# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU Affero General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Affero General Public License for more details.
#
# You should have received a copy of the GNU Affero General Public License
# along with this program. If not, see <https://www.gnu.org/licenses/>.
#
from typing import Optional, Any
import openpyxl
def menu_item_fix(s: str) -> Optional[str]:
if not s:
return None
if s == "Condiments Selection\n葱，香菜，榨菜丝，老干妈，生抽，醋":
return None
return s.strip().replace("Biscuit /", "Biscuit/").replace("Juice /", "Juice/").replace(" \n", "\n").replace("\n ", "\n")
def parse_meal_table(rows: list[Any], initrow: int, t: list[str]) -> dict[str, dict[str, list[str]]]:
assert rows[initrow + 1][1].value is None
igroups = []
i = initrow + 2
while True:
c = rows[i][1]
if not isinstance(c, openpyxl.cell.MergedCell):
igroups.append(i)
i += 1
if len(igroups) >= len(t):
break
wgroups = dict(zip(igroups + [i], t + [None]))
ret: dict[str, dict[str, list[str]]] = {}
kmap = {}
for k in range(2, 7):
ret[rows[initrow + 1][k].value[0:3]] = {}
kmap[k] = rows[initrow + 1][k].value[0:3]
i = 0
wgroupskeys = list(wgroups.keys())
while i < len(wgroupskeys) - 1:
wgroup = wgroups[wgroupskeys[i]]
assert wgroup is not None
for km in ret:
ret[km][wgroup] = []
for j in range(wgroupskeys[i], wgroupskeys[i + 1]):
for k in range(2, 7):
v = menu_item_fix(rows[j][k].value)
if v:
ret[kmap[k]][wgroup].append(v)
i += 1
return ret
def parse_menus(
filename: str,
) -> dict[str, dict[str, dict[str, list[str]]]]:
wb = openpyxl.load_workbook(filename=filename)
ws = wb["菜单"]
rows = list(ws.iter_rows())
final = {}
i = -1
while i < len(rows) - 1:
i += 1
row = rows[i]
if not isinstance(row[1].value, str):
continue
if "BREAKFAST" in row[1].value:
final["Breakfast"] = parse_meal_table(
rows,
i,
[
"Taste of Asia",
"Eat Global",
"Revolution Noodle",
"Piccola Italia",
"Self Pick-up", # instead of veg and soup
"Fruit/Drink",
],
)
elif "LUNCH" in row[1].value:
final["Lunch"] = parse_meal_table(
rows,
i,
[
"Taste of Asia",
"Eat Global",
"Revolution Noodle",
"Piccola Italia",
"Vegetarian",
"Daily Soup",
"Dessert/Fruit/Drink",
],
)
elif "DINNER" in row[1].value:
final["Dinner"] = parse_meal_table(
rows,
i,
[
"Taste of Asia",
"Eat Global",
"Revolution Noodle",
"Piccola Italia",
"Vegetarian",
"Daily Soup",
"Dessert/Fruit/Drink",
],
)
# elif "Students Snack" in row[1].value:
# parse_meal_table(rows, i)
return final
|
